For a saturable enzyme with Vmax = 1200 mg/h, Km = 6 mg/L, and S = 3 mg/L, what is CLint and how does it compare to the maximal CLint at low substrate (S→0)?

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Multiple Choice

For a saturable enzyme with Vmax = 1200 mg/h, Km = 6 mg/L, and S = 3 mg/L, what is CLint and how does it compare to the maximal CLint at low substrate (S→0)?

Explanation:
For a saturable enzyme, the rate follows Michaelis-Menten: v = (Vmax × S)/(Km + S). Intrinsic clearance at a given substrate level is CLint = v/S, which simplifies to CLint = Vmax/(Km + S). The maximal CLint occurs as S approaches zero and equals Vmax/Km. Plugging in the values: CLint = 1200 / (6 + 3) = 1200 / 9 = 133.3 L/h. The maximal CLint at very low substrate is 1200 / 6 = 200 L/h. So CLint at S = 3 mg/L is lower (133.3 L/h) than the maximal CLint at low substrate (200 L/h).

For a saturable enzyme, the rate follows Michaelis-Menten: v = (Vmax × S)/(Km + S). Intrinsic clearance at a given substrate level is CLint = v/S, which simplifies to CLint = Vmax/(Km + S). The maximal CLint occurs as S approaches zero and equals Vmax/Km.

Plugging in the values: CLint = 1200 / (6 + 3) = 1200 / 9 = 133.3 L/h. The maximal CLint at very low substrate is 1200 / 6 = 200 L/h.

So CLint at S = 3 mg/L is lower (133.3 L/h) than the maximal CLint at low substrate (200 L/h).

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